9a^2-32=0

Solution for 9a^2-32=0 equation:

9a^2-32=0

a = 9; b = 0; c = -32;
Δ = b2-4ac
Δ = 02-4·9·(-32)
Δ = 1152
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1152}=\sqrt{576*2}=\sqrt{576}*\sqrt{2}=24\sqrt{2}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24\sqrt{2}}{2*9}=\frac{0-24\sqrt{2}}{18}
=-\frac{24\sqrt{2}}{18}
=-\frac{4\sqrt{2}}{3}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24\sqrt{2}}{2*9}=\frac{0+24\sqrt{2}}{18}
=\frac{24\sqrt{2}}{18}
=\frac{4\sqrt{2}}{3}
$